(x-2)^2+13=40

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Solution for (x-2)^2+13=40 equation: 



(x-2)^2+13=40

We move all terms to the left:

(x-2)^2+13-(40)=0

We add all the numbers together, and all the variables

(x-2)^2-27=0

We move all terms containing x to the left, all other terms to the right

(x-2)^2=27

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